好久没写博客,贡献一份高质量代码。高质量代码其实思路上没什么特别的,只是编程细节上面做了些优化。
Your runtime beats 96.73% of cppsubmissions!
Given a list of non negative integers, arrange them such that they form the largest number.
For example, given [3, 30, 34, 5, 9], the largest formed number is 9534330.
Note: The result may be very large, so you need to return a string instead of an integer.
使用贪心算法解决问题,重载sort函数,使用字符串比较实现高位比较,不多说,上代码。
static inline bool cpr(const string& s1, const string& s2){
return s1 + s2 > s2 + s2;
}
class Solution {
public:
string largestNumber(const vector<int>& nums) {
stringstream ss;
vector<string> numstr(nums.size());
for (int i = 0; i < nums.size(); ++i){
ss.clear();
ss << nums[i];
ss >> numstr[i];
}
sort(numstr.begin(), numstr.end(), cpr);
string s;
for (int i = 0; i < numstr.size(); ++i){
s += numstr[i];
}
s.erase(0, s.find_first_not_of("0"));
if(!s.length()){
s = "0";
}
return s;
}
};
OK,See You Next Chapter!
