好久没写博客,贡献一份高质量代码。高质量代码其实思路上没什么特别的,只是编程细节上面做了些优化。
Your runtime beats 96.73% of cppsubmissions!
Given a list of non negative integers, arrange them such that they form the largest number.
For example, given [3, 30, 34, 5, 9]
, the largest formed number is 9534330
.
Note: The result may be very large, so you need to return a string instead of an integer.
使用贪心算法解决问题,重载sort函数,使用字符串比较实现高位比较,不多说,上代码。
static inline bool cpr(const string& s1, const string& s2){ return s1 + s2 > s2 + s2; } class Solution { public: string largestNumber(const vector<int>& nums) { stringstream ss; vector<string> numstr(nums.size()); for (int i = 0; i < nums.size(); ++i){ ss.clear(); ss << nums[i]; ss >> numstr[i]; } sort(numstr.begin(), numstr.end(), cpr); string s; for (int i = 0; i < numstr.size(); ++i){ s += numstr[i]; } s.erase(0, s.find_first_not_of("0")); if(!s.length()){ s = "0"; } return s; } };
OK,See You Next Chapter!